A satellite moves in a circular orbit of radius 4R round the earth. The acceleration of the satellite in terms of g is
\(\frac{g}{16}\)
\(\frac{g}{4}\)
\(\frac{4}{g}\)
\(\frac{16}{g}\)
Correct answer is A
\(\frac{g}{R^2}\) = \(\frac{g}{4^2}\) = \(\frac{g}{16}\)