200g of water at 90°C is mixed with 100g of water at ...
200g of water at 90°C is mixed with 100g of water at 30°C. What is the final temperature?
50oC
60oC
70oC
80oC
Correct answer is C
Heat lost = heat gained
200 x c x (90 - θ)= 100× c × (θ−30)
Dividing through by 100c, we have
2(90−θ) = (θ−30)
simplifying, we have
θ = 70°
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