If two charged plates are maintained at a potential difference of 3 kv, the work done in taking a charge of 600µc across the field is

A.

0.8j

B.

1.8j

C.

9.0j

D.

18.0j

View answer & explanation

Correct answer is B

Workdone = product of the charge Q, and the p.d V.

i.e Work done = QV
= 600 * 10-6 *2.1 * 103

=1.8j

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