Calculate the angle of minimum deviation of a 60º&nb...
Calculate the angle of minimum deviation of a 60º prism of a refractive index 1.5[ sin−1 (0.75) = 49º]
38o
19.47o
16.25o
49o
Correct answer is A
For a refractive index () = sin12(A+D)sin12A
D = angle of minimum deviation
A = refractive angle of the prism
1.5 = sin12(60+D)sin12×60
1.5 = sin12(60+D)sin30
Sin 12 (60 + D) = 1.5 * Sin 30
Sin 12 (60 + D) = 0.75
12 (60 + D) = Sin-1 (0.75)
but Sin-1 (0.75) = 49o
12 (60 + D) = 49
60 + D = 2 * 49 = 98o
D = 98o - 60o
D = 38o