A 12\(\Omega\) resistor dissipates 8kJ of heat in 20s. Calculate the current through the resistor
5.8A
6.9A
30.0A
33.3A
Correct answer is A
Q = I2Rt I = \(\sqrt{\frac{Q}{Rt}}\) = \(\sqrt{\frac{8000}{12 \times 20}}\) = 5.8
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