If the volume of a gas is recorded as 76cm3 at a temperature of 27°C with a pressure of 800mmHg. What will be the volume of the gas at S.T.P?
36.2cm3
25.7cm3
72.8cm3
24.3cm3
Correct answer is C
General formular of Gas laws
(P1V1) ÷ T1= (P2V2) ÷ T2
P1 = 800mmHg, V, = 76cm3, Tr = 273 + 27 = 300k
P2 = 760mmHg, V2 = ? T2= 273 + 0 = 273
(800 × 76) ÷ 300 = (760 × V2) ÷ 273
V2 = (300 × 76 × 273) ÷ (300 × 760) = 72.8 cm3
The volume of gas as S.T.P = 72.8 cm3
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