Two liquids X and Y having the same mass are supplied with the same quantity of heat. If the temperature rise in X is twice that of Y, the ratio of specific heat capacity of X to that of Y is

A.

2:1

B.

1:2

C.

4:1

D.

1:4

View answer & explanation

Correct answer is B

MC\(x_\theta\) = MC\(y_\theta\)

\(x_\theta\) = 2 \(\times y_\theta\)

MC(2\(y_\theta\)) = MC\(y_\theta\)

⇒ 2C = C

=1 : 2

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