In a meter bridge experiment, two resistor 2\(\Omega\) and 3\(\Omega\) occupy the left and right gaps respectively. Find the balance point from the left side of the bridge

A.

20cm

B.

40cm

C.

60cm

D.

80cm

Correct answer is B

Let the point be x

\(\frac{2}{x}\) = \(\frac{3}{100 - x}\)

making x subject of formula,

2(100 - x) = 3x

200 - 2x = 3x

200 = 3x + 2x

200 = 5x

divide both side by 5

x = 40cm