A ray of light is incident at an angle of 30^o on a glass prism of refractive index 1.5. Calculate the angle through which the ray is minimally deviated in the prism. (The medium surrounding the prism is air)

10.5^o

19.5^o

21.1^o

38.9^o

40.5^o

Correct answer is A

n = \(\frac{sin i}{sin r}\)

sin r = \(\frac{30^o}{n}\)

sin r = \(\frac{0.5}{1.5}\)

sin r = 0.3333

r = 19.5^o; Deviation 30 - 19.5 = 10.5^o

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A ray of light is incident at an angle of 30o on a glass prism of refractive index 1.5. Calculate the angle through which the ray is minimally deviated in the prism. (The medium surrounding the prism is air)