\(\frac{5}{6}\)
11
3\(\frac{3}{5}\)
2\(\frac{1}{2}\)
1\(\frac{1}{5}\)
Correct answer is D
x \(\alpha\) y = x \(\alpha\) \(\frac{1}{z}\)
x \(\alpha\) \(\frac{1}{z}\)
x = k \(\frac{y}{z}\)
k = \(\frac{xz}{y}\) = \(\frac{9 \times 8}{24}\)
= 3
x = \(\frac{xz}{y}\)
= \(\frac{3 \times 5}{6}\)
= \(\frac{15}{6}\)
= \(\frac{5}{2}\)
= 2\(\frac{1}{2}\)