$In the figure, $\bigtriangleup$PQT is isosceles. PQ = QT, SRQ = 35o, TPQ = 20o and PQR is a straight line.Calculate TSR$

In the figure, $\bigtriangleup$PQT is isosceles. PQ = QT, SRQ = 35^o, TPQ = 20^o and PQR is a straight line.Calculate TSR

20^o

55^o

75^o

140^o

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Correct answer is C

Given $\bigtriangleup$ isosceles PQ = QT, SRQ = 35^o

TPQ = 20^o

PQR = is a straight line

Since PQ = QT, angle P = angle T = 20^o

Angle PQR = 180^o - (20 + 20) = 140^o

TQR = 180^o - 140^o = 40^o < on a straight line

QSR = 180^o - (40 + 35)^o = 105^o

TSR = 180^o - 105^o

= 75^o

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In the figure, \(\bigtriangleup\)PQT is isosceles. PQ = QT, SRQ = 35^o, TPQ = 20^o and PQR is a straight line.Calculate TSR

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In the figure, \(\bigtriangleup\)PQT is isosceles. PQ = QT, SRQ = 35o, TPQ = 20o and PQR is a straight line.Calculate TSR

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In the figure, \(\bigtriangleup\)PQT is isosceles. PQ = QT, SRQ = 35^o, TPQ = 20^o and PQR is a straight line.Calculate TSR