Simplify $\frac{\sqrt{2}}{\sqrt{3} - \sqrt{2}}$ - $\frac{3 - 2}{\sqrt{3} + \sqrt{2}}$

2 $\sqrt{2} - \sqrt{3}$

3( $\sqrt{6}$ - 1)

$\sqrt{6}$ - 3

- $\frac{1}{2}$

$\frac{-\sqrt{3}}{\sqrt{2} - \sqrt{2}}$

Correct answer is B

$\frac{\sqrt{2}}{\sqrt{3} - \sqrt{2}}$ - $\frac{3 - 2}{\sqrt{3} + \sqrt{2}}$

$\frac{\sqrt{2}}{\sqrt{3} - \sqrt{2}}$ = $\frac{\sqrt{2}}{\sqrt{3}}$ - $\frac{x}{\sqrt{2}}$

$\frac{\sqrt{3} + \sqrt{2}}{3 + \sqrt{2}}$ = $\sqrt{6}$ + 2

$\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}$ = $\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}$ x $\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}}$

= 5 - 2 $\sqrt{6}$

$\sqrt{6}$ + 2 - (5 - 2 $\sqrt{6}$ ) = $\sqrt{6}$ + 2 - 5 + 2 $\sqrt{6}$

= 3 $\sqrt{6}$ - 3

= 3( $\sqrt{6}$ - 1)

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