(52, 1)
(5, -4)
(2, 1)
(1, −52)
(1,-2)
Correct answer is D
22r−1 - 53 = 1r+2
22r−1 - 1r+2 = 53
2r+4−2r+12r−1(r+2) = 53
5(2r+1)(r+2) = 53
5(2r - 1)(r + 2) = 15
(10r - 5)(r + 2) = 15
10r2 + 20r - 5r - 10 = 15
10r2 + 15r = 25
10r2 + 15r - 25 = 0
2r2 + 3r - 5 = 0
(2r2 + 5r)(2r + 5) = r(2r + 5) - 1(2r + 5)
(r - 1)(2r + 5) = 0
r = 1 or −52
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