In this figure, PQ = PR = PS and SRT = 68<sup>o</sup>. Find QPS
A.
136o
B.
124o
C.
12o
D.
68o
Correct answer is A
Since PQRS is quadrilateral 2y + 2x = QPS = 360o
i.e. 2(y + x) + QPS = 360o
QPS = 360o - 2(y + x)
But x + y + 68o = 180o
x + y = 180o - 68o = 180o
x + y = 180o - 68o
= 112o
QPS = 360o - 2(112o)
360o - 224o = 136o