In the diagram, PR is a diameter, ∠PRQ = (3x-8)° ...
In the diagram, PR is a diameter, ∠PRQ = (3x-8)° and ∠RPQ = (2y-7)°. Find x in terms of y
x=75−2y3
x=105−3y2
x=105−2y3
x=75−3y2
Correct answer is C
180 = ∠RPQ + ∠PRQ + ∠PQR Since PQR = 90 (theorem: angle in a semi circle)
180 = ∠RPQ + ∠PRQ + 90 => 180° = (3x-8)°+(2y-7)°+90°; 90+8+7 = 3x+2y =>105−2y3=x
If loga3 = m and loga5 = p, find loga75...
p = |x302y3424| Q = \(\begin{vmatrix} x ...
(4√3+4√2)(4√3−4√2)(√3+√2) is equal to...
Simplify 3.72 x 0.025 and express your answer in the standard form...
In the figure, PQRS is a circle. If chords QR and RS are equal, calculate the value of x ...
The graph of y = ax2+bx+c is shown oon the diagram. Find the minimum value of y...
A circular arc subtends angle 150° at the centre of a circle of radius 12cm. Calculate the ...
If the value of π is taken to be 227, the area of a semi-circle of diameter 42m i...