Find the probability that a number selected at random from 40 to 50 is a prime
\(\frac{5}{11}\)
\(\frac{5}{11}\)
\(\frac{3}{11}\)
\(\frac{4}{11}\)
Correct answer is C
From 40 to 50 = these number are prime i.e. 41, 43, 47
prob. of selecting a prime No. is \(\frac{3}{11}\)