If $\frac{3e + f}{3f - e}$ = $\frac{2}{5}$ , find the value of $\frac{e + 3f}{f - 3e}$

$\frac{5}{2}$

$\frac{26}{7}$

$\frac{1}{3}$

Correct answer is C

$\frac{3e + f}{3f - e}$ = $\frac{2}{5}$

= 3e + f

= 2 x 1

$\frac{-e + 3f}{3e - f}$ = $\frac{5 \times 3}{2}$

= $\frac{3e + 9f = 15}{10f = 17}$

f = $\frac{17}{10}$

Sub. for equ. (1)

3e + $\frac{17}{10}$ = 2

3e = 2 - $\frac{17}{10}$

$\frac{3}{10}$

e = $\frac{3}{10}$ x $\frac{1}{3}$

= $\frac{1}{10}$

= e + 3f = $\frac{1}{10}$ + $\frac{3 \times}{10}$ = $\frac{52}{10}$

f - 3e = $\frac{17}{10}$ - 3 x $\frac{1}{10}$

= $\frac{14}{10}$

= $\frac{52}{10}$ x $\frac{10}{14}$

= $\frac{26}{7}$

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