Four interior angles of a pentagon are 90^o - x^o, 90^o + x^o, 110^o - 2x^o, 110^o + 2x^o. Find the fifth interior angle

110^o

120^o

130^o

140^o

Correct answer is D

Let the fifth interior angle be y: sum of interior angle of a pentagon

= (2 x 5 - 4) x 90^o

= 6 x 90^o

= 540^o

(90 - x) + (90 + x) + (110 - 2x) + (110 + 2x) + y = 540^o

400^o + y = 540^o

y = 540 - 400^o

y = 140^o

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Four interior angles of a pentagon are 90o - xo, 90o + xo, 110o - 2xo, 110o + 2xo. Find the fifth interior angle

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Four interior angles of a pentagon are 90^o - x^o, 90^o + x^o, 110^o - 2x^o, 110^o + 2x^o. Find the fifth interior angle