150o
110o
100o
95o
Correct answer is C
L + 30o - 180o(Sum of < s on straight line)
L = 180o - 30o = 150o
L = q = 150o(opposite < s are equal)
y = b = 30o(alt. < s)
b + c = 180o(sum of < s on str. line)
30o + c 180
c = 180 - 30
c = 150o
b = a = 30o (opp < s are equal)
c = d = 150o (opp < s are equal)
a + k + 70o = 180o (sum of < s on \(\bigtriangleup\))
30o + k + 70o = 180
k + 100o = 180
k = 180 - 100
k = 80o
x + 80o = 180(sum of < s on straight line)
x = 180o - 80o
x = 100o
What is the value of x when y = 5? y = \(\frac{1}{2}\) x + 1...
Evaluate \(\int^2_1(x^2 - 4x)dx\)...
Find the median of 2, 1, 0, 3, 1, 1, 4, 0, 1 and 2 ...
Evaluate, correct to four significant figures, (573.06 x 184.25). ...
If \(\frac{2}{x-3}\) - \(\frac{3}{x-2}\) = \(\frac{p}{(x-3)(x -2)}\), find p....
Find n if log\(_{2}\) 4 + log\(_{2}\) 7 - log\(_{2}\) n = 1...