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If the surface area of a sphere increased by 44%, find th...

If the surface area of a sphere increased by 44%, find the percentage increase in diameter

A.

44

B.

30

C.

22

D.

20

Correct answer is D

Surface Area of Sphere A = 4πr2

∴ A = 4π(D)22

= (D)22

= πD2

When increased by 44% A = 144πD2100

π(12D)210 = π(6D)25

Increase in diameter = 6D5 - D = 15D

Percentage increase = 15 x 1100%

= 20%