If the surface area of a sphere increased by 44%, find th...
If the surface area of a sphere increased by 44%, find the percentage increase in diameter
44
30
22
20
Correct answer is D
Surface Area of Sphere A = 4πr2
∴ A = 4π(D)22
= (D)22
= πD2
When increased by 44% A = 144πD2100
π(12D)210 = π(6D)25
Increase in diameter = 6D5 - D = 15D
Percentage increase = 15 x 1100%
= 20%
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