In the diagram, AB is a vertical pole and BC is horizontal. If |AC| = 10m and |BC| = 5m, calculate the angle of depression of C from A
A.
63o
B.
60o
C.
45o
D.
27o
Correct answer is B
In triangle ABC, \(\frac{BC}{AC} = \cos \theta\)
\(\implies \cos \theta = \frac{5}{10} = 0.5\)
\(\theta = \cos^{-1} (0.5) = 60°\)