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Given that $\theta$ is an acute angle and sin $\theta$ =...

Given that $\theta$ is an acute angle and sin $\theta$ = $\frac{m}{n}$ , find cos $\theta$

A.

$\frac{\sqrt{n^2 - m^2}}{m}$

B.

$\frac{\sqrt{(n + m)(n - m)}}{n}$

C.

$\frac{m}{\sqrt{n^2 - m^2}}$

D.

$\sqrt{\frac{n}{n^2 - m^2}}$

View answer & explanation

Correct answer is B

sin $\theta$ = $\frac{m}{n}$

Opp = m; Hyp = n

Adj = $\sqrt{n^{2} - m^{2}}$

$\cos \theta = \frac{\sqrt{n^{2} - m^{2}}}{n}$

= $\frac{\sqrt{(n + m)(n - m)}}{n}$

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