323
4
413
423
Correct answer is D
∫1−1(2x+1)2dx
= ∫1−1(4x2+4x+1)dx
= ∫1−1[4x33+2x2+x]
= [43 + 2 + 1] - [−43+2 -1]
= 133 + 13
= 143
= 423
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