In the diagram above, ∠PTQ = ∠URP = 25° ...
In the diagram above, ∠PTQ = ∠URP = 25° and XPU = 4URP. Calculate ∠USQ.
100o
120o
125o
130o
150o
Correct answer is D
Since < URP = 25°, then < XPU = 4 x 25° = 100°
∴ < TPQ = 180° - 100° = 80°
\therefore < PQT = 180° - (80° + 25°) = 75°
< SQR = 75° - 25° = 50° (exterior angle = 2 opp interior angles)
\therefore < USQ = 180° - 50° = 130°
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