-5 \(\leq\) x v 8
5 \(\leq\) x \(\leq\) 8
-8 \(\leq\) x \(\leq\) 5
-5 < x \(\leq\) 8
Correct answer is C
To solve -11 \(\leq\) 4 - 3x \(\leq\) 28
-11 \(\leq\) 4 - 3x also 4 -3x \(\leq\) 28
15 \(\leq\) -3x \(\leq\) 24 = 15 \(\geq\) 3x - 3x \(\geq\) -24
-5 \(\geq\) x, x \(\geq\) -8
i.e. x \(\leq\) 5
∴ -8 \(\leq\) x \(\leq\) 5
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