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Solve for y in the equation 10^1 x 5(2y - 2) x 4(y - 1)...

Solve for y in the equation 10^1 x 5(2y - 2) x 4(y - 1) = 1

A.

$\frac{3}{4}$

B.

$\frac{5}{4}$

C.

$\frac{2}{3}$

D.

5

View answer & explanation

Correct answer is C

10y x 5(2y - 2) x 4(y - 1) = 1

but 10y - (5 x 2)y = 5y x 2y

= (Law of indices)

5y x 2y x 5(2y - 2) x 4(y - 1) = 1

but 4(y - 1) = 22(y - 1)

= 2y - 2 (Law of indices)

5y x 5(2y -2) x 2(- 2) = 1

5(3y -2) x 2y x 2(2y -2) = 1

= 5(3y -2) x 2(3y -2) = 1

But ao = 1

10(3y -2) = 10o

3y - 2 = 0

∴ y = $\frac{2}{3}$

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