-\(\frac{1}{3}\)
\(\frac{1}{2}\)
\(\frac{1}{3}\)
-\(\frac{1}{2}\)
Correct answer is D
\(\frac{\log_3 9 - \log_2 8}{\log_3 9}\)
= \(\frac{\log_3 3^2 - \log_2 2^3}{\log_3 3^2}\)
= \(\frac{2 -3}{2}\)
= \(\frac{-1}{2}\)
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