Given that p=1+√2 and q=1−√2,...
Given that p=1+√2 and q=1−√2, evaluate p2−q22pq.
2(2+√2)
-2(2+√2)
2√2
-2√2
Correct answer is D
p2−q22pq=(p+q)(p−q)2pq
= (1+√2−(1−√2))(1+√2+1−√2)2(1+√2)(1−√2)
= (2√2)(2)−2
= −2√2
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