x + y \(\leq\) 3
x + y < 3
x + y > 3
x + y \(\geq\) 3
Correct answer is B
Using \(\frac{x}{a} + \frac{y}{b}\) < 1for the equation of the time
where a = intercept on x-axis and b = intercept on y - axis
\(\frac{x}{3} + \frac{y}{3} = 1\)
= \(\frac{x + y}{3} = 1\)
= x + y < 3