The bearing of P from Q is x, where 270o < x < 360o. Find the bearing of Q from P
A.
(x - 90)o
B.
(x-270)o
C.
(x - 135)o
D.
(x - 180)o
Correct answer is D
Bearing of Q and P
\(180^{\circ} – (360^{\circ}-x)\\
180^{\circ}-360^{\circ}+x\\
-180^{\circ}+x\\
x-180^{\circ}\)