\(-\frac{3}{2}\)
\(\frac{1}{3}\)
-1
-3
Correct answer is C
\(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\\ 3^{1-n}\times 3^{-2(-2n)} = 3^{-2}\\ 1-n-2(-2n)= -2\\ 1-n+4n=-2\\ n=-1\)
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