\frac{\sqrt{b^2 - a^2}}{b}
1\frac{-a}{b}
\frac{b^2 - a^2}{b}
\frac{a^2 - b^2}{b}
\sqrt{b^2 - a^3}
Correct answer is A
\sin x = \frac{a}{b}
\sin^{2} x + \cos^{2} x = 1
\sin^{2} x = \frac{a^{2}}{b^{2}}
\cos^{2} x = 1 - \frac{a^{2}}{b^{2}} = \frac{b^{2} - a^{2}}{b^{2}}
\therefore \cos x = \frac{\sqrt{b^{2} - a^{2}}}{b}
\sin (90 - x) = \sin 90 \cos x - \cos 90 \sin x
= (1 \times \frac{\sqrt{b^{2} - a^{2}}}{b}) - (0 \times \frac{a}{b})
= \frac{\sqrt{b^{2} - a^{2}}}{b}
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