To arrive on schedule, a train is to cover a distance of ...
To arrive on schedule, a train is to cover a distance of 60km at 72km/hr. If it starts 10 minutes late, at what speed must it move to arrive on schedule?
60km/hr
80km/hr
90km/hr
108km/hr
Correct answer is C
speed=distancetime72=60timet=6072=56hr
time lost = 10mis =1060hr=16
Time required for the journey
=56−16=23speed=60÷23=90km/hr
Solve the equation 3 + 5x - 2x2 = 0...
A cylindrical container, closed at both ends, has a radius of 7cm and height 5cm [Take π = 22/7] ...
IN the diagram, |LN| = 4cm, LNM = 90o and tan y = 2/3. What is the area of the ∆LMN?...
Solve for x, If 2x1p2+1p2 = m...
If y = (2√x2+m)3N, make x the subject of the formular...
Simplify (x - 3y)2 - (x + 3y)2...
If cos θ = x and sin 60o = x + 0.5 0o < θ < 90o, find, correct to the nearest degr...