\(-\frac{1}{2},-3\)
2, 3
-2, 3
\(-\frac{1}{2},3\)
Correct answer is D
\(3 + 5x - 2x^2 = 0\\
3 + 6x - x - 2x^2 = 0\\
3(1 + 2x) - x(1 + 2x) = 0\\
(3-x)(1+2x)=0\\
3-x = 0 \hspace{1mm}or \hspace{1mm}1+2x = 0\\
x = 3\hspace{1mm} x = -\frac{1}{2}\\
x = 3 \hspace{1mm}or\hspace{1mm} x =-\frac{1}{2}\)
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