Solve for x, If \(\frac{\frac{2}{x}}{\frac{1}{p^2} + \frac{1}{p^2}}\) = m

A.

\(\frac{4pq}{m(p + q)}\)

B.

\(\frac{2p^2q^2}{m(q^2 + p^2)}\)

C.

\(\frac{2pq}{m(q^2 + p^2)}\)

D.

\(\frac{2p^2q^2}{m(p^2)}\)

Correct answer is B

\(\frac{1}{p^2}\) + \(\frac{1}{q^2}\) = \(\frac{q^2 + p^2}{p^2 + q^2}\)

\(\frac{\frac{2}{x}}{\frac{p^2 + q^2}{p^2 q^2}}\)

m = \(\frac{2p^2q^2}{x(p^2 + q^2)}\)

= m2p2q2 = m x (p2 + q2)

x = \(\frac{2p^2q^2}{m(q^2 + p^2)}\)