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If A = \(\begin{pmatrix} 2 & 1 \\ 2 ...

If A = (212312) and B = (3242). Find AB

A.

(1861210106)

B.

(1061310126)

C.

(1061210116)

D.

(1061810116)

Correct answer is D

Given A = (212312) and B = (3242).

We can multiply these matrices since the number of colums in A = number of rows in B

 

AB = ((23)+(14)(22)+(12)(23)+(34)(22)+(32)(13)+(24)(12)+(22))

 

AB = ((6+4)(4+2)(6+12)(4+6)(3+8)(2+4))

 

= (1061810116)