M varies directly as n and inversely as the square of p. If M = 3, when n = 2 and p = 1, find M in terms of n and p.
M = 2n/3p
M = 3n2/2p2
M = n2/2p
M = 3n/2p2
M = 2n/3p2
Correct answer is D
\(M \propto \frac{n}{p^2}\)
\(M = \frac{kn}{p^2}\)
\(3 = \frac{k(2)}{1^2}\)
\(3 = 2k \implies k = \frac{3}{2}\)
\(M = \frac{3n}{2p^2}\)