In a triangle XYZ, if < ZYZ is 60, XY = 3cm and YZ = 4cm, calculate the length of the sides XZ.
√23cm
√13cm
2√5cm
2√3cm
Correct answer is B
(XZ)2 = 32 + 42 - 2 x 3 x 4 cos60o = 25 - 24\(\frac{1}{2}\) XZ = √13cm
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