y < -10
y < -2
y < 2
y < 10
Correct answer is B
multiply both sides by the LCM
12 x \(\frac{y+2}{4}\) - 12 x \(\frac{y-1}{3}\) >12 x 1
3[y+2] - 4[y-1] > 12
3y + 6 - 4y + 4 > 12
-y + 2 > 12
-y > 12 - 10 = 2
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