How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
x < 4
x > -4
x < -4
x > 4
Correct answer is C
3(x + 2) > 6(x + 3)
3x + 6 > 6x + 18
3x - 6x > 18 - 6
-3x > 12
x < -4
If r varies inversely as the square root of s and t, how does s vary with r and t?
s varies inversely as r and t2
s varies inverely as r2 and t
s varies directly as r2 and t2
s varies directly as r and t
Correct answer is B
\(r \propto \frac{1}{\sqrt{s}}, r \propto \frac{1}{\sqrt{t}}\)
\(r \propto \frac{1}{\sqrt{s}}\) ..... (1)
\(r \propto \frac{1}{\sqrt{t}}\) ..... (2)
Combining (1) and (2), we get
\(r = \frac{k}{\sqrt{s} \times \sqrt{t}} = \frac{k}{\sqrt{st}}\)
This gives \(\sqrt{st} = \frac{k}{r}\)
By taking the square of both sides, we get
st = \(\frac{k^2}{r^2}\)
s = \(\frac{k^2}{r^{2}t}\)
12\(\frac{8}{5}\)
15
10
28\(\frac{8}{5}\)
Correct answer is C
P \(\propto\) mu, p \(\propto \frac{1}{q}\)
p = muk ................ (1)
p = \(\frac{1}{q}k\).... (2)
Combining (1) and (2), we get
P = \(\frac{mu}{q}k\)
4 = \(\frac{m \times u}{1}k\)
giving k = \(\frac{4}{6} = \frac{2}{3}\)
So, P = \(\frac{mu}{q} \times \frac{2}{3} = \frac{2mu}{3q}\)
Hence, P = \(\frac{2 \times 6 \times 4}{3 \times \frac{8}{5}}\)
P = \(\frac{2 \times 6 \times 4 \times 5}{3 \times 8}\)
p = 10
The remainder when 6p3 - p2 - 47p + 30 is divided by p - 3 is
21
42
63
18
Correct answer is B
Let f(p) = 6p3 - p2 - 47p + 30
Then by the remainder theorem,
(p - 3): f(3) = remainder R,
i.e. f(3) = 6(3)3 - (3)2 - 47(3) + 30 = R
162 - 9 - 141 + 30 = R
192 - 150 = R
R = 42
If x - 4 is a factor of x2 - x - k, then k is
4
12
20
2
Correct answer is B
Let f(x) = x2 - x - k
Then by the factor theorem,
(x - 4): f(4) = (4)2 - (4) - k = 0
16 - 4 - k = 0
12 - k = 0
k = 12