The remainder when 6p3 - p2 - 47p + 30 is divided by p - 3 is

A.

21

B.

42

C.

63

D.

18

View answer & explanation

Correct answer is B

Let f(p) = 6p3 - p2 - 47p + 30

Then by the remainder theorem,

(p - 3): f(3) = remainder R,

i.e. f(3) = 6(3)3 - (3)2 - 47(3) + 30 = R

162 - 9 - 141 + 30 = R

192 - 150 = R

R = 42

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