Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,956.

Find \(\alpha\) and \(\beta\) such that x\(\frac{3}{8}\) x y\(\frac{-6}{7}\) x (\(\frac{y^{\frac{9}{7}}}{x^{\frac{45}{8}}}\))\(\frac{1}{9}\) = \(\frac{y^{\alpha}}{y^{\beta}}\)

A.

\(\alpha\) = 1, \(\beta\) = \(\frac{5}{7}\)

B.

\(\alpha\)= 1, \(\beta\) = -\(\frac{5}{7}\)

C.

\(\alpha\)= \(\frac{3}{5}\), \(\beta\) = -6

D.

\(\alpha\)= 1, \(\beta\) = -\(\frac{3}{5}\)

Correct answer is A

x\(\frac{3}{8}\) x y\(\frac{-6}{7}\) x (\(\frac{y^{\frac{9}{7}}}{x^{\frac{45}{8}}}\))\(\frac{1}{9}\) = \(\frac{y^{\alpha}}{y^{\beta}}\)

x\(\frac{3}{8}\) x y\(\frac{-6}{7}\) x y\(\frac{1}{7}\) = x\(\alpha\)

= x\(\frac{3}{8}\) + \(\frac{5}{8}\) + y\(\frac{6}{7}\) + \(\frac{1}{7}\)

= x\(\alpha\)y\(\beta\)

x1y\(\frac{-5}{7}\) = x\(\alpha\)y\(\beta\)

\(\alpha\) = 1, \(\beta\) = \(\frac{5}{7}\)

1,957.

Write the equation 2 log2x - x log2(1 + y) = 3 in a form not involving logarithms

A.

2x(1 + y) = 3

B.

2x - x(1 + y) = 8

C.

x2 = 8(1 + y)x

D.

x2 - x(1 + y) = 8

E.

x2 - (1 + y)2 = 8

Correct answer is C

2log2 x - x log2 (1 + y) = 3

log2 \(\frac{x^2}{(1 + y)^x}\) = 3

= \(\frac{x^2}{(1 + y)^x}\)

= 23

= 8

1,958.

The graphical method of solving the equation x3 + 3x2 + 4x - 28 = 0 is by drawing the graphs of the curves

A.

y = x3 and y = 3x2 + x - 28

B.

y = x3 + 3x2 + 4x + 4 and the line y = \(\frac{28}{x}\)

C.

y = x3 + 3x2 + 4x and y

D.

y = x2 + 3x + 4 and y = \(\frac{28}{x}\)

E.

y = x2 + 3x + 4 and line y = 28x

Correct answer is D

The graphical method of solving the equation x3 + 3x2 + 4x - 28 = 0 is by drawing the graphs of the curves

y = x2 + 3x + 4 and y = \(\frac{28}{x}\)`.

1,959.

The solution of the quadratic equation bx2 + cx + a = 0 is given by

A.

x = b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2a}\)

B.

x = c \(\pm\) \(\frac{\sqrt{b^2 - 4ab}}{2b}\)

C.

x = -c \(\pm\) \(\frac{\sqrt{c^2 - 4ab}}{2b}\)

D.

x = -b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2b}\)

Correct answer is C

bx2 + cx + a = 0

a = b; b = c; c = a

x = -b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2a}\)

x = -c \(\pm\) \(\frac{\sqrt{c^2 - 4ab}}{2b}\)

1,960.

The factors of 6x - 5 - x2 are

A.

-(x + 3)(x + 2)

B.

(x + 5)(x + 1)

C.

(x - 5)(1 - x)

D.

(x + 1)(x + 5)

Correct answer is C

6x - 5 - x2 = (-1)(-x2 - 5 + 6x) = x2 - 6x + 5 = (x - 5)(x - 1) -(x - 1) = 1 - x = (x - 5)(1 - x)