The solution of the quadratic equation bx2 + cx + a = 0 is given by

A.

x = b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2a}\)

B.

x = c \(\pm\) \(\frac{\sqrt{b^2 - 4ab}}{2b}\)

C.

x = -c \(\pm\) \(\frac{\sqrt{c^2 - 4ab}}{2b}\)

D.

x = -b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2b}\)

Correct answer is C

bx2 + cx + a = 0

a = b; b = c; c = a

x = -b \(\pm\) \(\frac{\sqrt{b^2 - 4ac}}{2a}\)

x = -c \(\pm\) \(\frac{\sqrt{c^2 - 4ab}}{2b}\)