Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,506.

N140,000 is shared between Abu, Kayode and Uche. Abu has twice as much as Kayode and Kayode has twice as much as Uche. What is Kayode'sshare?

A.

N80,000

B.

N40,000

C.

N2,000

D.

10,000

Correct answer is B

Let Abu's share = 2x;

Kayode's = x

Uche's share = \(\frac{x}{2}\)

Total: 2x + x + \(\frac{x}{2}\) = N140,000

\(\frac{7x}{2}\) = N140,000

x = \(\frac{280,000}{7}\) = N40,000

Kayode's share = N40,000

1,507.

Simplify \(\frac{3x^3}{(3x)^3}\)

A.

1

B.

\(\frac{1}{3}\)

C.

\(\frac{1}{9}\)

D.

\(\frac{1}{27}\)

Correct answer is C

\(\frac{3x^3}{(3x)^3}\) = \(\frac{3 \times x^3}{3^3 \times x^3}\)

= \(\frac{3 \times x^3}{3 \times 3 \times 3 \times x^3}\)

= \(\frac{1}{3^2}\)

= \(\frac{1}{9}\)

1,508.

Which of the following statement is true for the ste P = {-3.2 \(\leq\) x < 5} where x is an integer?

A.

least value of x is -3.2

B.

least value of x is -3

C.

greatest value of x is 4.9

D.

greatest value of x is 5

Correct answer is B

p = {-3.2.....4.9}; Since x is an integer

least value of x is -3

1,509.

Simplify 3\(\sqrt{45} - 12\sqrt{5} + 16\sqrt{20}\), leaving your answer in surd form.

A.

29\(\sqrt{5}\)

B.

14\(\sqrt{15}\)

C.

12\(\sqrt{15}\)

D.

11\(\sqrt{15}\)

Correct answer is A

3 \(\sqrt{45} - 12\sqrt{5} + 16\sqrt{20}\)

= 3 x \(\sqrt{9 \times 5} - 12 \times \sqrt{5} + 16 \times \sqrt{4 \times 5}\)

= 3 x 3 x \(\sqrt{5} - 12 \times \sqrt{5} + 16 \times 2 \times \sqrt{5}\)

= 9\(\sqrt{5} - 2 \sqrt{5} + 32 \sqrt{5}\)

= 9\(\sqrt{5} + 32\sqrt{5} - 12\sqrt{5}\)

= 29\(\sqrt{5}\)

1,510.

If p \(\alpha \frac{I}{Q}\) which of the following is true?

A.

q \(\alpha p^2\)

B.

q \(\alpha \frac{1}{p^2}\)

C.

q \(\alpha \sqrt{p}\)

D.

q \(\alpha \frac{1}{p}\)

Correct answer is D

p \(\alpha \frac{I}{Q}\); p \(\frac{k}{q}\) (where k is constant)

q = \(\frac{k}{p}\)

q \(\alpha \frac{1}{p}\)