How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
14 years
20 years
12 years
16 years
Correct answer is D
M + L = 28,
M : L = 600 : 800
= 3 : 4
\(\frac{M}{L}\) = \(\frac{3}{4}\) \(\to\) M = \(\frac{3}{4}\)L
\(\frac{3}{4}\)L + L = 28
\(\frac{7L}{4}\) = 28
L = \(\frac{4 \times 28}{7}\)
= 16
If y = (1 + x)2, find \(\frac{dy}{dx}\)
x - 1
2 + 2x
1 + 2x
2x - 1
Correct answer is B
If y = (1 + x)2, find \(\frac{dy}{dx}\)
y = (1 + x)2
\(\frac{dy}{dx}\) = 2(1 + x)
= 2 + 2x
184m
185m
186m
187m
Correct answer is D
Tan 20° = \(\frac{68m}{x}\)
x tan 20° = 68
x = \(\frac{68}{tan 20}\) = \(\frac{68}{0.364}\)
x = 186.8
= 187m
Calculate the distance between points L(-1, -6) and M(-3, -5)
√5
2√3
√20
√50
Correct answer is A
L\(\begin{pmatrix} x_1 & y_1 \\ -1 & -6 \end{pmatrix}\) m L\(\begin{pmatrix} x_2 & y_2 \\ -3 & -5 \end{pmatrix}\)
D = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
D = \(\sqrt{(-3 - (-1)^2 + (-5 -(-6)^2}\)
D = \(\sqrt{(-3 + 1)^2 + (-5 + 6)^2}\)
D = \(\sqrt{(-2)^2 + 1^2}\)
D = \(\sqrt{4 + 1}\)
D = \(\sqrt{5}\)
-\(\frac{1}{8}\)
\(\frac{3}{8}\)
\(\frac{5}{8}\)
\(\frac{1}{4}\)
Correct answer is D
-2p + r = 1.......(i)
2p + 3r = 0.......(ii)
r - 1 + 2p ........(iii)
2p + 3(1 + 2p) = 0
2p + 3(1 + 2p) = 0
2p + 3 + 6p = 0
3 - 8p = 0 \(\to\) 8p = 3
p = \(\frac{3}{8}\)
6 = 1 - 2 \(\frac{3}{8}\)
= 1 - \(\frac{6}{8}\)
\(\frac{8 - 6}{8}\) = \(\frac{2}{8}\)
= \(\frac{1}{4}\)