√5
2√3
√20
√50
Correct answer is A
L(x1y1−1−6) m L(x2y2−3−5)
D = √(x2−x1)2+(y2−y1)2
D = √(−3−(−1)2+(−5−(−6)2
D = √(−3+1)2+(−5+6)2
D = √(−2)2+12
D = √4+1
D = √5
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