How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Make t the subject of formula S = ut + \(\frac{1}{2} at^2\)
\(\frac{1}{a}\) (-u + \(\sqrt{U^2 - 2as}\))
\(\frac{1}{a}\) {u \(\pm\) (U2 - 2as)}
\(\frac{1}{a}\) {u \(\pm\) \(\sqrt{2as}\)}
\(\frac{1}{a}\) {-u + \(\sqrt{( 2as)}\)}
Correct answer is A
Given S = ut + \(\frac{1}{2} at^2\)
S = ut + \(\frac{1}{2} at^2\)
∴ 2S = 2ut + at2
= at2 + 2ut - 2s = 0
t = \(\frac{-2u \pm 4u^2 + 2as}{2a}\)
= -2u \(\pi\) \(\frac{\sqrt{u^2 4u^2 + 2as}}{2a}\)
= \(\frac{1}{a}\) (-u + \(\sqrt{U^2 - 2as}\))
Solve the equation: \(y - 11\sqrt{y} + 24 = 0\)
8, 3
64, 9
6, 4
9, -8
Correct answer is B
\(y - 11\sqrt{y} + 24 = 0 \implies y + 24 = 11\sqrt{y}\)
Squaring both sides,
\(y^{2} + 48y + 576 = 121y\)
\(y^{2} + 48y - 121y + 576 = 0 \implies y^{2} - 73y + 576 = 0\)
\(y^{2} - 64y - 9y + 576 = 0\)
\(y(y - 64) - 9(y - 64) = 0\)
\((y - 9)(y - 64) = 0\)
\(\therefore \text{y = 64 or y = 9}\)
Factorize \(9p^2 - q^2 + 6qr - 9r^2\)
(3p - 3q + r)(3p - q - 3r)
(6p - 3q - 3r)(3p - q - 4r)
(3p - q + 3r)(3p + q - 3r)
(3q - p + 3r)(3q - p + 3r)
Correct answer is C
\(9p^{2} - q^{2} + 6qr - 9r^{2}\)
= \(9p^{2} - (q^{2} - 6qr + 9r^{2})\)
= \(9p^{2} - (q^{2} - 3qr - 3qr + 9r^{2})\)
= \(9p^{2} - (q(q - 3r) - 3r(q - 3r))\)
= \(9p^{2} - (q - 3r)^{2}\)
= \((3p + (q - 3r))(3p - (q - 3r))\)
= \((3p + q - 3r)(3p - q + 3r)\)
(0)
U
(8)
\(\phi\)
Correct answer is D
U = (1, 2, 3, 6, 7, 8, 9, 10)
E = (10, 4, 6, 8, 10)
F = (x : x\(^2\) = 2\(^6\), x is odd)
∴ F = \(\phi\) Since x\(^2\) = 2\(^6\) = 64
x = \(\pm 8\) which is even
∴ E ∩ F = \(\phi\) Since there are no common elements
(2, 4, 3, 5, 11) and (4)
(4, 3, 5, 11) and (3, 4)
(2, 5, 11) and (2)
(2, 3, 5, 11) and (2)
Correct answer is D
x = (all prime factors of 44) and y = (all prime factors of 60)
∴ x = (2, 11), y = (2, 3, 5)
X ∪ Y = (2, 3, 5, 11),
X ∩ Y = (2)