How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify \(\frac{4\frac{3}{4} - 6\frac{1}{4}}{4\frac{1}{5} \text{ of } 1\frac{1}{4}}\)
-7\(\frac{7}{8}\)
\(\frac{-2}{7}\)
\(\frac{-10}{21}\)
\(\frac{10}{21}\)
Correct answer is B
\(\frac{4\frac{3}{4} - 6\frac{1}{4}}{4\frac{1}{5} \text{ of } 1\frac{1}{4}}\)
\(\frac{19}{4}\) - \(\frac{25}{4}\)............(A)
\(\frac{21}{5}\) x \(\frac{5}{4}\).............(B)
Now work out the value of A and the value of B and then find the value \(\frac{A}{B}\)
A = \(\frac{19}{4}\) - \(\frac{25}{4}\)
= \(\frac{-6}{4}\)
B = \(\frac{21}{5}\) x \(\frac{5}{4}\)
= \(\frac{105}{20}\)
= \(\frac{21}{4}\)
But then \(\frac{A}{B}\) = \(\frac{-6}{4}\) \(\div\) \(\frac{21}{4}\)
= \(\frac{-6}{4}\) x \(\frac{4}{21}\)
= \(\frac{-24}{84}\)
= \(\frac{-2}{7}\)
\(\frac{5}{12}\)
\(\frac{1}{3}\)
\(\frac{3}{4}\)
\(\frac{7}{12}\)
Correct answer is D
Coca-cola = 10 bottles, Fanta = 8 bottles
Sprite = 6 bottles, Total = 24
P(cola-cola) = \(\frac{10}{24}\)
P(not coca-cola) = 1 - \(\frac{10}{24}\)
\(\frac{24 - 10}{24}\) = \(\frac{14}{24}\)
= \(\frac{7}{12}\)
96
94
92
90
Correct answer is A
% of boxes containing at least 5 defective bolts each
= \(\frac{7 + 17 + 10 + 8 + 6}{50}\)
= \(\frac{48}{50}\) x \(\frac{100}{1}\)
= 96%
6.7, 6
7.6, 5
5.7, 87
34, 6
Correct answer is A
| No of defective(x) | No of boxes (f) | \(fx\) |
| 4 | 2 | 8 |
| 5 | 7 | 35 |
| 6 | 17 | 102 |
| 7 | 10 | 70 |
| 8 | 8 | 64 |
| 9 | 6 | 54 |
| \(\sum\) | 50 | 333 |
\(Mean = \frac{\sum fx}{\sum f}\)
= \(\frac{333}{50} = 6.66 \approxeq 6.7\)
The median is the average of the 25th and 26th position = 6.
76.8o and 25.2o
10.8o and 224.6o
112.4o and 72.0o
39.6o and 212.4o
Correct answer is D
Education = 11% = \(\frac{11}{100} \times 360° = 39.6°\)
Food = 59% = \(\frac{59}{100} \times 360° = 212.4°\)