Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result
\(\begin{array}{c|c} \text{No. defective per box} & 4 & 5 & 6 & 7 & 8 & 9 \\ \hline \text{No. of boxes} & 2 & 7 & 17 & 10 & 8 & 6\end{array}\)
Find the percentage of boxes containing at least 5 defective bolts each

A.

96

B.

94

C.

92

D.

90

Correct answer is A

% of boxes containing at least 5 defective bolts each

= \(\frac{7 + 17 + 10 + 8 + 6}{50}\)

= \(\frac{48}{50}\) x \(\frac{100}{1}\)

= 96%