6.7, 6
7.6, 5
5.7, 87
34, 6
Correct answer is A
| No of defective(x) | No of boxes (f) | \(fx\) |
| 4 | 2 | 8 |
| 5 | 7 | 35 |
| 6 | 17 | 102 |
| 7 | 10 | 70 |
| 8 | 8 | 64 |
| 9 | 6 | 54 |
| \(\sum\) | 50 | 333 |
\(Mean = \frac{\sum fx}{\sum f}\)
= \(\frac{333}{50} = 6.66 \approxeq 6.7\)
The median is the average of the 25th and 26th position = 6.